32*(1/2)^(x+1)=(2)^x-14

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Solution for 32*(1/2)^(x+1)=(2)^x-14 equation: 



32(1/2)^(x+1)=(2)^x-14

We move all terms to the left:

32(1/2)^(x+1)-((2)^x-14)=0



Domain of the equation: 2)^(x+1)!=0

x∈R



We add all the numbers together, and all the variables

32(+1/2)^(x+1)-(2^x-14)=0

We get rid of parentheses

32(+1/2)^(x+1)-2^x+14=0

We multiply all the terms by the denominator


32(+1-2^x*2)^(x+1)+14*2)^(x+1)=0

We add all the numbers together, and all the variables

32(+1-2^x*2)^(x+1)+14*2)^(x=0

Wy multiply elements

32(+1-2^x*2)^(x+1)+28x=0

We add all the numbers together, and all the variables

28x+32(+1-2^x*2)^(x+1)=0

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